Let \(S\) be an affine set. Pick any point \(x_0 \in S\), and define: \[
V = \{x - x_0 \mid x \in S\}
\]
This set \(V\) is a vector subspace of \(\mathbb{R}^n\), because affine sets are closed under affine combinations, and subtraction cancels the translation offset.
Since \(V\) is a subspace, it can be written as the null space of some matrix \(A \in \mathbb{R}^{m \times n}\): \[
V = \{x \in \mathbb{R}^n \mid A x = 0\}
\]
Hence the original affine set is: \[
S = \{x \in \mathbb{R}^n \mid A(x - x_0) = 0\}
= \{x \in \mathbb{R}^n \mid A x = A x_0\}
\]
Let \(b = A x_0\). Then: \[
S = \{x \in \mathbb{R}^n \mid A x = b\}
\]
So \(S\) is the solution set of a system of linear equations.
✅ Q.E.D.